600=3.14(r^2)

Solution for 600=3.14(r^2) equation:

600=3.14(r^2)

We move all terms to the left:

600-(3.14(r^2))=0

We get rid of parentheses

-3.14r^2+600=0

a = -3.14; b = 0; c = +600;
Δ = b2-4ac
Δ = 02-4·(-3.14)·600
Δ = 7536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7536}=\sqrt{16*471}=\sqrt{16}*\sqrt{471}=4\sqrt{471}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{471}}{2*-3.14}=\frac{0-4\sqrt{471}}{-6.28}
=-\frac{4\sqrt{471}}{-6.28}
=-\frac{2\sqrt{471}}{-3.14}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{471}}{2*-3.14}=\frac{0+4\sqrt{471}}{-6.28}
=\frac{4\sqrt{471}}{-6.28}
=\frac{2\sqrt{471}}{-3.14}
$